how many grams of Ag will be produced from 5.00g of Cu and 1.00g of AgNO3

Question

Cu+2AgNO3→2Ag+Cu(NO3)2

Answer 1

From the balanced equation, it can be seen that 1 mole of Cu reacts with 2 moles of AgNO₃ to produce 2 moles of Ag.

1.  Determine moles of each reactant.

2.  Determine which reactant is limiting.

3.  Determine moles of Ag formed.

4.  Determine mass of Ag formed.

 

1.  moles Cu = 5.00 g Cu x 1 mole Cu/63.5 g = 0.0787 moles Cu

moles AgNO₃ = 1.00 g x 1 mole AgNO₃/170 g = 0.00588 moles AgNO₃

2.  Limiting reactant = AgNO₃

3.  Moles of Ag formed = 0.00588 moles AgNO₃ x 2 moles Ag/2 moles AgNO₃ = 0.00588 moles Ag formed

4.  Grams Ag formed = 0.00588 moles Ag x 108 g/mole = 0.635 g Ag formed (to 3 significant figures)