Four lengths measuring 6 1/4 inches, 9 3/16 inches, 7 1/8 inches and 5 9/32 inches are cut from 48 inches of cable. How much is left?

Question

Four lengths measuring 6 1/4 inches, 9 3/16 inches, 7 1/8 inches and 5 9/32 inches are cut from 48 inches of cable. How much is left? 

Answer 1

The common denominator is 32...

The sum of:

6 and 1/4

9 and 3/16

7 and 1/8

5 and 9/32

 

becomes:

  6 and 8/32

  9 and 6/32

 8 and 4/32

 5 and 9/32

 

which is :

  28 and 27/32

 

48 minus this total is:

 

 19 and 5/32