The width of a rectangular park is 4m shorter than its length. If the area of the park is 320m2, find the dimensions of the park

Question

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Answer 1

First, let's write down the system of 2 equations with 2 unknown variables: W (width) and L (length) as following

 

L - W = 4 (because width is 4m shorter than length)

LW = 320 (the area)

 

Substitute W = 320/L

 

L - 320/L = 4

 

or to put it in canonical form:

 

L² - 4L - 320 = 0

 

This quadratic equation has 2 solutions, but only one positive: L = 20. Therefore, W = 16.

 

The answer: L (length) = 20m, W (width) = 16m