Solving for a gaseous reactant

Question

Write a balanced chemical equation, including physical state symbols, for the combustion of liquid heptane into gaseous carbon dioxide and gaseous water.

Suppose 0.270 kg of heptane are burned in air at a pressure of exactly 1 atm and a temperature of 11.0 C. Calculate the volume of carbon dioxide gas that is produced. 

Answer 1

C7H16(l) + 11 O2(g) ——> 7 CO2(g) + 8 H2O(g)

MW Heptane = (12*7)+(16*1) = 84 + 16 = 100 g/mol

 

0.27 kg Hep*(1000 g/1kg) = 270 g Hep

270 g Hep*(1mol Hep/100g)*(7 mol CO2/1 mol Hep) = 18.9 mol CO2

 

PV = nRT ——> V = nRT/P

T in K

P in atm

 

V = 18.9mol*0.08206L*atm/(mol*K)*284 K/1atm

 

V = 440.5 L