Would the HCL affect the calculation of molarity ?

Question

If you forgot to fill the tip of the buret with HCL solution before starting the standardization of your NaOH solution, how would this affect the calculated molarity of NaOH from the data you recorded? Would this calculated molarity be greater or less than the actual molarity? Brief explain your reasoning

Answer 1

If the tip isn't filled, then the initial movement of the meniscus in the buret will be taken as volume of HCl added to the NaOH, when in fact, it never was added to the NaOH.  This will result in a calculated molarity of NaOH GREATER than the actual molarity.