volume of a 0.143 M sodium hydroxide is required to neutralize 19.5ml of a 0.127 M Hydrochloric

Question

What volume of a 0.143 M sodium hydroxide solution is required to neutralize 19.5 mL of a 0.127 M hydrochloric acid solution?


_____mmL sodium hydroxide

Answer 1

NaOH + HCl ==> NaCl + H2O

moles HCl present = 0.0195 L x 0.127 mol/L = 0.0024765 moles

moles of NaOH needed =  0.0024765 moles

(0.143 mol/L)(x L) =  0.0024765 moles

x = 0.01732 L = 17.3 ml NaOH