
Kris V. answered 04/23/18
Tutor
5
(36)
Experienced Mathematics, Physics, and Chemistry Tutor
x2 = 4 sec2t
= 4(1 + tan2t)
= 4 + 4 tan2t
= 4 + 4y2
x2 – 4y2 = 4
If you reduce the above equation to its standard form
x2/22 – y2/12 = 1
you will see that it is the equation of a hyperbola centered at (0,0) with a = 2, b = 1 and a horizontal transverse axis.