
Arturo O. answered 04/20/18
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You need to calculate 4 different heat transfers and then add them to get the total heat transfer.
m = 115.0 g
(1)
You will heat ice from -11.0°C to the freezing point of water at 0°C. Look up the specific heat of ice. Call it c1.
ΔT1 = [0 - (-11.0)]°C
Q1 = mc1ΔT1
(2)
You will melt ice at a constant temperature of 0°C. Look up the latent heat of fusion of water, lf.
Q2 = mlf
(3)
You will heat liquid water from 0°C to the boiling point of water at 100°C. Look up the specific heat of liquid water. Call it c3.
ΔT3 = (100 - 0)°C
Q3 = mc3ΔT3
(4)
You will vaporize the water at a constant temperature of 100°C. Look up the latent heat of vaporization of water, lv.
Q4 = mlv
The total heat transfer required is
Q = Q1 + Q2 + Q3 + Q4
Plug in the numbers, and be careful with units.