J.R. S. answered 04/17/18
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You have volume 1 (V1) which is 13.5 liters.
You have temperature 1 (T1) which is 25ºC. Change this to K = 25 = 273 = 298 K
You have temperature 2 (T2) which is 10ºC. Change this to K = 10 + 273 = 283 K
You are asked to find volume 2 (V2). This assumes that the pressure (P) is constant, i.e. same indoors and outside.
This involves Charles' Law
V1/T1 = V2/T2
13.5 L/298 K = V2/283 K
V2 = (13.5 L)(283 K)/298K
V2 = 12.8 liters