C Program Question

Question

The height of an object thrown upward with a velocity v is given by
h(t)=vt-0.5gt^2
where t is time in sec and g is 9.81 m/s2. Write a C program to compute the height of the object at an interval of 0.1 s. Stop the computation when the object reaches the maximum height at time t=v/g. The program should read in the value of the velocity v and display the maximum height.

 

I already tried this: 

#include <stdio.h>
main(){

float h,t,v,g=9.81,maxH=0,maxT;

h=v*t-0.5*g*pow(t,2);

for(t=0;t<(v/g);t=t+0.1){

printf("Enter the value of v :\n");
scanf("%f", &v);


if(t>maxT)
t=maxT;

}


printf("\n\nThe Largest height is %f",h);
}

 

but still not working

 

Answer 1

#include <stdio.h>

#define G (9.81f)

int main()

{

float v;

float t=0;

float h;

float maxT;

printf(" Please input the intial veloctiy :>");

scanf("%f",&v);

maxT = v/G;

printf(" max height occurs at t = %6.2f \n",maxT);

while (t< maxT)

{

h = v*t - 0.5*G*t*t;

t = t + 0.1;

printf(" t = %6.2f and height h = %6.2f \n",t,h);

}

printf(" Max height is %8.3f \n",h);

printf(" Max height at %8.3f \n",v*maxT-0.5*G*maxT*maxT);

}