tangent line Calc AB

Question

At what point on the graph of y=(1/2)x^2 - (3/2) is the tangent line parallel to the line 4x-8y=5?

Answer 1

First, find the slope of the line 4x - 8y = 5:

 

      -8y = -4x + 5

 

         y = (1/2)x - (5/8)     Slope = 1/2

 

Next, find the value of x specified in the problem's statement:

 

       Slope of tangent = y' = x

 

       Since the tangent line is parallel to the given line, we have x = 1/2

 

Point on the graph:  (1/2,  (1/2)(1/2)² - 3/2) = (1/2, -11/8)

 

Answer 2

previous answer withdrawn because of a silly error.