Let B = he speed of the bus, then (2B-6) is the speed of the airplane
Let T= the time of travel for each
The BT=186 and (2B-6)T=354
Therefore 186/B = 354/(2B-6)
Cross multiply and collect terms => 372B-1116 = 354B => 18B=1118
B=62 and airplane speed 118