J.R. S. answered 04/05/18
Tutor
5.0
(145)
Ph.D. in Biochemistry--University Professor--Chemistry Tutor
HCl + NaHCO3 ==> H20 + CO2 + NaCl
Let us say that we want to generate 0.900 L of CO2 gas so it will fill the bag but it will not pop the bag.
From PV = nRT we can solve for n (moles of CO2 needed to get 0.9 L)
n = PV/RT = (1 atm)(0.900 L)/(0.0821 Latm/Kmol)(295K)
n = 0.0372 moles of CO2 needed
From the balanced equation we see that ONE mole HCl reacts with ONE mole NaHCO3 to make ONE mole CO2.
So, we will nee 0.0372 moles of HCl and 0.0372 moles NaHCO3 to make 0.0372 moles CO2
I cannot tell you the number of liters of HCl and NaHCO3 because you didn't supply the molarity or concentration of either. If you have the molarity of each, you can calculate the number of liters of each that will be needed.