A titration done to standardize a solution of NaOH requires 15.7 mL of NaOH for 0.610 g of KHP. What is the concentration of the NaOH solution?

Question

A titration done to standardize a solution of NaOH requires 15.7 mL of NaOH for 0.610 g of KHP. What is the concentration of the NaOH solution?

Answer 1

moles of KHP = 0.610 g x 1 mol/204 g = 0.002990 moles

NaOH and KHP react in a 1:1 mole ratio so moles NaOH = mole KHP

Concentration of NaOH = 0.00299moles NaOH/0.0157 L = 0.190 mole/L = 0.190 M (3 sig figs)