√A box is being constructed by cutting 3 inch squares from a rectangular sheet of cardboard that is 3 inches longer than it is wide. If the box is to have a volume of 324 cubic inches, find the dimensions of the sheet of cardboard.
18 in by 18 in
9 in by 36 in
159 in by 162 in
15 in by 18 in
18 in by 18 in
9 in by 36 in
159 in by 162 in
15 in by 18 in
Solution:
The volume of the box is V = 324 in3. The box is a cube with volume
V=S3 where S is the length of the side S=3√ V = 3√ 324 = 6.87 in
the surface area of the box is six faces of A = S2 = 6.872 = 47.2 in2
the total area needed to construct the box is = 6 x 47.2 in2 = 283.2 in2
the length of the card board sheet is L = W+3 , Since L >W then it sis a rectangular shape. the required area of the cardboard sheet is
LW=283.2 in2 ...eq1 and L=W+3 ...eq2 substitute 2nd eq into 1st eq
(W+3)W=283.2 , W2+3W=283.2,
W2+3W-283.2=0 Solve Quadratic equation
W=[-3±√(3)2-4(1)(-283.2)]/2 = [-3±√1141.8]/2=(-3±33.79)/2
Two roots,
W=(-3+33.79/2) and W =(-3-33.79/2)
W=15.4 W=- 18.4
W should be positive W =15.4 in, L =W+3=15.4+3= 18.4in