How must the integers 1 to 12 be divided into 3 groups so that when one integer from each group is picked, the sum of them must equal a number between 6 and 29?

Question

Please, I have to know the answer within 24 hours, if you could answer it as quick as possible, it would be great. Thanks!

Answer 1

Basically you want the 3 smallest numbers, 1 per group, to add to 6,

and the 3 largest numbers in each group to add to 29.

 

Group 1:  1     4     5    8

Group 2:  2     6     7    9

Group 3:  3    10   11   12

 

Smallest total of 1 number from each group:  1+2+3 = 6

Largest total of 1 number from each group:    8+9+12 = 29

 

You can play with the orders between the groups, especially 4, 5, 6, 7;

but 1, 2, 3 must be the smallest numbers with each in a separate set,

and 8, 9, 12 the largest numbers with each in a separate set.