Areeba N.

asked • 03/19/18

1.19 gm of SOCl2 is added up in 100ml H2O.Find molarity of H+ in the solution such obtained.(assume 100% dissociation of acids formed).

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J.R. S. answered • 03/19/18

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Ph.D. in Biochemistry--University Professor--Chemistry Tutor
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What is hm?  I'm assuming you are given a certain mass or number of moles of SOCl2 which is then dissolved in a final volume of 100 ml H2O.  Not knowing what 1.19 is, it's difficult to answer.
SO2Cl + H2O ==> 2HCl + SO2 so HCl is the acid formed
Let's assume you had 1.19 mmole (again don't know what the hm is supposed to be), then you'd have
1.19 mmole/100 ml = 11.9 mmoles/L = 11.9 mM = 11.9x10-3 M = 1.19x10-2 M
[H+] = 1.19x10-2 M
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Areeba N.

Sr that meant 'hm'  meant gm  and the answer is given as 0.4M and mine is coming 0.2M. as according to the equation 1mole of SOCl2 forms 2 mole HCl..Can you please explain how the ans should be 0.4M or plz tell that it's given wrong in my book.
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03/24/18

J.R. S.

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Ok.  Also, I notice that I mis-typed the equation in the original answer.  It should be SOCl2 and NOT SO2Cl.  Anyway...
SOCl2 + H2O ==> 2HCl + SO2
1.19 g SOCl2 x 1 mole/119 g = 0.01 moles SOCl2
moles HCl formed = 0.01 moles SOCl2 x 2 moles HCl/mole SOCl2 = 0.02 moles HCl formed
Molarity of H+ = 0.02 mole/0.1 L = 0.2 M
You are correct, and the book is wrong.
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03/24/18

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