what is the vertex of the parabola whos equation is y=x2=+4x+8?

Question

what is the vertex of the parabola whose equation is y=^x2=+4x+8?

Answer 1

Another method would be to convert to (h,k) form....

 

y = x² + 4x + 8

  = x² + 4x + 4 + 4

  = (x² + 4x + 4) + 4

  = (x + 2)² + 4

 

This shows the vertex is (-2, 4)

Answer 2

(-2,4)  Use VP = ( -b/2a, f(-b/2a)