
Emily M. answered 03/12/18
Tutor
5.0
(63)
University of Rochester Grad for Math and Science Tutoring
The BF3 molecule has sp2 hybridization. In this molecule Boron has to form three equivalent bonds, one with each F atom, leading to sp2 hybridization. Boron has three valence electrons, 2 s electrons and 1 p. In this configuration, there is only one unpaired electron in Boron's valence shell. One s electron is promoted up to a p level and then the one s orbital and 2 p orbitals mix to form three equivalent sp2 orbitals, each with one electron that can each take on one electron from a F atom, forming the three necessary bonds. It helps to visualize this by writing out the electron configurations before hybridization and after hybridization.