Mark M. answered 03/11/18
Tutor
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Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
y = f(x) = (9x+5)½
differential of f = dy = df = f'(x)dx = (1/2)(9x+5)-1/2(9)dx
= 9/[2√(9x+5)]dx
b. Δf = f(4.1) - f(4) ≈ df = f'(4)(4.1-4)
= 9/[2√41](0.1) ≈ 0.070
c. Δy = Δf = f(4.1) - f(4) = √41.9 - √41 ≈ 0.0698967 ≈ 0.070