Kenneth S. answered 03/04/18
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This is not phrased properly. Find equation of a quadratic having zeros (roots) 2 and 3, and y intercept 6.
f(x) = y = a(x-2)(x-3),
f(0) = a(-2)(-3) = 6 so a=1.
f(x) = (x-2)(x-3).