Michael P. answered 02/27/18
Tutor
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Quick Answers to Math, Chemistry, and Physics Problems
D = distance (mile) = rate (mph) x time (hr)
Let R = boat speed in still water (mph)
C = current speed = 6 mph
t1 = 11 hr = time boat travels distance D with current C
t2 = 14 hr = time boat travels distance D against current C
with current: D = (R + C)*t1
against current: D = (R - C)*t2
Set D's equal and solve for R:
(R + 6)*11 = (R - 6)*14
11*R + 66 = 14*R - 84
3*R = 150
R = 150/3 = 50 mph in still water