Joe S. answered • 09/11/14

Tutor

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Advanced degrees in Business, Finance, and Statistics

You can simplify things a bit by finding R6, the equivalent resistance of R1 and R2 in parallel = 2*6/8 = 1.5.

Call i6 the current thru R6 (in the same direction as i2).

Looking at the node for currents i6, i4, and i3, they must sum to 0, so i3+i4+i6=0

we know i4 = -11 from the current source, so i3+i6 = 11

The voltages across the resistors must sum to the voltage source of 6V

v3 = i3*R3

v6=i6*R6

6*i3 -1.5*i6 = 6

Solving gives i3 = 3, i6 = 8

v3 = +18V

v6 = -12 V

sum is +6V as required.

You can then find the currents in R1 and R2 using 12V across each one, which add to i6