a mean of 444 and a standard deviation of 52 what percentage of students scored between 288 and 600 on the exam?

Question

this problem includes z charts and finding the percentage

Answer 1

The scores are:

 

    (228 - 444)/52 = -4.1538

 

    AND

  (600-444)/52 = 3

 

  So the Prob(  -4.1538 < z < 3 ) =

 

           Prob ( z < 3 ) - Prob (  z < -4.1538)

 

           = 0.9987     -      0

 

           = 0.9987

 

Note that the latter probability could not be found on the table, as the smallest

 z-score is -3.4 with probability 0.0003