
Larry C. answered 02/22/18
Tutor
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Computer Science and Mathematics professional
Let s represent the price of a senior ticket and c that of a child. Therefore, the first day can be represented by
3s + c = 38
Solving for c in terms of s gives us
c = 38 - 3s
Plugging that into the expression for the 2nd day
3s + 2c = 52 = 3s + 2(38-3s) = 3s + 76 - 6s = 76-3s
Solving for s
52 = 76 - 3s
52 - 52 + 3s = 76 - 52 - 3s + 3s
3s = 24
s = 8
c = 38 - 3(8) = 38 - 24 = 14
Note that in this instance, an easier solution would be to note that the only difference between sales for the two days was that of a single child ticker and $14 more was earned the second day so the price of a child ticket being $14 is quickly determined.