ZnBr2(aq)+Na2(aq)---> ZnS(s)+NaBr(aq)

Question

Write the net ionic equation for this reaction

 

Answer 1

The equation presented cannot be correct because there is no S on the left side. Assuming that you meant 

ZnBr₂(aq) + Na₂S(aq) ==> ZnS(s) + NaBr(aq), then...

When a precipitate (s) is formed, the easiest way to write the net ionic equation is to find the elements/molecules that make up the precipitate and they will be the only reactants. In this case, you are looking for Zn and S as reactants and ZnS(s) as the product.  So, you would have Zn²⁺(aq) + S^2-(aq) ==> ZnS(s) as the NET IONIC EQUATION