These two questions are quite alike, but I cannot use the same method for them and it seems like the second problem considers the order while the first does not

Question

1) Tina and Tricia play on a softball team. Tina has 8 hits out of 20 times at bat, and Tricia has 6 hits out of 16 times at bat. Based on their past performance, what is the probability that both girls will get a hit the next time they bat? (Answer: 3/20)

2) There are 20 people at a competition, including Bob and his two friends. Each competitor has an equal chance of winning a prize and no one can win more than one prize. What is the probability that Bob and both of his friends each will win a prize? (Answer is 1/1140 and this is possible only if the six orders are considered and are multiplied. But the thing is why the order is not considered in the first problem)

Answer 1

(1)     Tina 8/20 = 4/10 = 2/5 = 0.4 = 40%

        Tricia 6/16 = 3/8 = 0.375 = 37.5%

 

        Probability of both = 2/5 * 3/8 = 6/40 = 3/20

         because they are independent events (one batter does not affect the probability of the other)

 

 (2)  3/20 * 2/19 * 1/18 =  1/1140