Raymond B. answered 08/16/21
Math, microeconomics or criminal justice
f(x) = 2x + 3
g(x) = x -3/2
f(g(x)) = 2(x-3/2) + 3 = 2x-3+3 = 2x
g(f(x)) = (2x+3)-3/2 = 2x+3/2
they are not inverses
y=2x+3
x=2y+3
2y =x-3
y = x/2 -3/2 = f^-1(x) = the inverse of f(x) but g(x) is x-3/2 not x/2-3/2
for g(x) switch x and y to get x=y-3/2, y=x+3/2 = g^-1(x)
b)
f(x) =-6x
g(x) =-6x
f(g(x)) = f(-6x) = -6(-6x) = 36x
g(f(x)) = g(-6x) = -6(-6x) = 36x
y=-6x
x=-6y
y = -x/6 = f^-1(x) = g^-1(x)
f^-1(f(x)) = f^-1(-6x) = -(-6x)/6 = x