
Michael P. answered 02/17/18
Tutor
New to Wyzant
Quick Answers to Math, Chemistry, and Physics Problems
a)
n = n0*2^(t/td)
where: n is the total number of sample bacteria
n0 is the initial number of sample bacteria = 10
td is the time the bacteria doubles (hr)
t is the final time (hr)
'2' represents 'it doubles'
b) n = 10*2^(4 hr/0.5 hr) Note: 0.5 hr equal 30 min
n = 10*2^(8) = 10*256 = 2560 bacteria after 4 hrs
c) n = 10*2^(6/0.5) = 10*2^(12) =10*4096 = 40,960 bacteria after 6 hrs