Michael P. answered 02/17/18
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Quick Answers to Math, Chemistry, and Physics Problems
n = n0*2^(t/td)
where: n is the total number of sample bacteria
n0 is the initial number of sample bacteria = 18 bacteria
td is the time the bacteria doubles = 2 hr
t is the final time (hr)
'2' represents 'it doubles'
b) n = 18*2^(8 hr/2 hr)
n = 18*2^(4) = 18*16= 288 bacteria after 8 hrs
c) n = 18*2^(16 hr/2 hr) = 18*2^(8) =18*256 = 4608 bacteria after 16 hrs
where: n is the total number of sample bacteria
n0 is the initial number of sample bacteria = 18 bacteria
td is the time the bacteria doubles = 2 hr
t is the final time (hr)
'2' represents 'it doubles'
b) n = 18*2^(8 hr/2 hr)
n = 18*2^(4) = 18*16= 288 bacteria after 8 hrs
c) n = 18*2^(16 hr/2 hr) = 18*2^(8) =18*256 = 4608 bacteria after 16 hrs