Confused Chem student, plz help

Question

How many grams of carbon monoxide are produced when 2.00 moles of butyne are combusted? The combustion of liquid butyne (tetracarbon hexahydride) with limited oxygen gas produces carbon monoxide gas and water. (Answer with 3 sigfigs AND NO UNITS i.e 987)

Answer 1

2C₄H₆ + 7O₂ ==> 8CO + 6H₂O  Balanced equation for incomplete combustion of butyne

moles CO produced = 2.00 moles butyne x 8 moles CO/2 moles butyne = 8.00 moles CO produced

Mass CO produced = 8.00 moles CO x 28 g/mole CO = 224 g CO

Answer = 224