Kenneth S. answered 01/31/18
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Expert Help in Algebra/Trig/(Pre)calculus to Guarantee Success in 2018
Eligible k values run from 1 to 25, any of which would have to be split into two factors that differ by ten.
obviously 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11 won't work, nor will 25.
What about 12? (x+12)(x-2) = 0 i.e. x2 + 10x -24.
I leave it to you to determine if any other k values (13 to 22) will work.