
Bobosharif S. answered 01/30/18
Tutor
4.4
(32)
Mathematics/Statistics Tutor
z=tan(a/2) = √[(1 - cos(a))/(1 +cos(a))]
z2=(1 - cos(a))/(1 +cos(a))
z2(1+cos(a))=1 - cos(a)
z2-1=-cos(a)(1+z2)
cos(a)=(1-z2)/(1+z2)
sin2(a)=1-cos2(a)=1-[(1-z2)/(1+z2)]2=
=((1+z2)2-(1+z2)2)/(1+z2)2
=4z2/(1+z2)2
sin2(a)=2z/(1+z2)
=1