Write an equation of a line that passes through the point (4,3) and is perpendicular to the graph of the equation y=−13x+4

Question

I need to get it into slope intercept form. I do not know remotely what to do for this.

Answer 1

First, find the slope of the equation perpendicular to the first line equation:

y = -13x + 4

To do this, you must know that the product of the original slope and the perpendicular slope must be -1.

m * m_perp = -1
m_perp = -1 / m
m_perp = -1 / (-13) = 1/13

Now that we know the slope, and we know the perpendicular line passes through (4,3), we can solve for the y-intercept.
y = m*x + b
3 = (1/13)*4 + b
b = 3 - 4/13 = 35/13

With the slope and y-intercept (b), the perpendicular line equation follows:

y = 1/13x + 35/13