For problems 1 and 2, factor first, then cancel common factors.
1. (x2-12x+32)/(x2-6x-16) • (x+2)/(x2-16)
= (x-8)(x-4)/[(x-8)(x+2)]•(x+2)/[(x-4)(x+4)]
= 1/(x+4)
Problem 2 is done in a similar manner.
For problems 3 and 4, find the LCD, then add or subtract.
4. (x+2)/(x-6) - (x2+5x+14)/(x2-2x-24)
= (x+2)/(x-6) - (x2+5x+14)/[(x-6)(x+4)]
= (x+2)(x-6)/[(x-6)(x+4)] - (x2+5x+14)/[(x-6)(x+4)]
= (x2-4x-12)/[(x-6)(x+4)] - (x2+5x+14)/[(x-6)(x+4)]
= (-9x-26)/[(x-6)(x+4)]
Do problem 3 in a similar way.