Glucose breaks down into elements by the unbalanced formula C6H12O6 → C + H + O. Given a sample of 0.280 moles of Glucose, how many moles of Carbon will be coll

Question

A. 0.280 mol C
B. 1.00 mol C
C. 1.12 mol C
D. 1.68 mol C
E. 6.00 mol C

Answer 1

Since the number of moles of C is 6 times that of a mole of C₆H₁₂O₆, then there must be 6 times the number of moles of C per mole of glucose.  Hence, 6 x 0.280 = 1.68 moles, D.