Arturo O. answered • 01/01/18

Experienced Physics Teacher for Physics Tutoring

First, we need to fix the equation. The first term should have t

^{2}in it.h(t) = -16t

^{2}+ 48t + 160It reaches maximum height at the vertex of the height-time parabola, which is at

t = -48/[2(-16)] s = 1.5 s

h

_{max}= h(1.5) = -16(1.5^{2}) + 48(1.5) + 160 = 196 ftIt reaches the ground when h(t) = 0

-16t

^{2}+ 48t + 160 = 0t

^{2}- 3t - 10 = 0(t - 5)(t + 2) = 0

t = 5 or -2

Since time starts at t=0, discard -2, so it reaches the ground 5s after launch.

Andy C.

01/01/18