J.R. S. answered 12/16/17
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Ph.D. in Biochemistry--University Professor--Chemistry Tutor
In both cases there will be an increase in entropy.

J.R. S.
tutor
That will depend on the specific heat of each gas under the condition stated. So at constant pressure
ΔS = Cp ln(T2/T1)
and at constant volume
ΔS = Cv ln (T2/T1)
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12/16/17
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12/16/17