ΔE = q - w
In this equation, q is the amount of heat added to the system and w is the amount of work done by the system.
In the problem, work is done on the system so w is negative, and heat is given off so q is also negative.
ΔE = -26kJ - -74kJ
ΔE = -26kJ + 74 kJ
ΔE = 48kJ
Because ΔE is positive, the energy of the gas increases.
Cherry M.
12/15/17