Ideal Gas Law Chemistry

Question

If 9.83 moles of an ideal gas has a pressure of 4.64 atm, and a volume of 31.49 L, what is the temperature of the sample?

 

K =?

Answer 1

The Ideal Gas Law is

PV = nRT

If you rearrange the formula to solve for Temperature(T) that becomes

T = PV / nR

Then for this set of values that means

T = (4.64 atm x 31.49 L) / (9.83 mol x 0.0821 L atm / mol K) = 181.05

meaning that the temperature of the gas is 181.05 K

Answer 2

Given the conditions, we can use the ideal gas law equation and solve for the temperature variable:

PV = nRT
(4.24 atm)(31.49 L) = (9.83 moles)(0.08206 atm.L/mol.K)(T)
[(4.24 atm)(31.49 L)]/[(9.83 moles)(0.08206 atm.L/mol.K)]=T
T =165 K