Ideal Gas Law

Question

If 32.5 moles of an ideal gas is at 4.39 atm at 6.40 °C, what is the volume of the gas?

 

L = ?

Answer 1

the Ideal Gas Law is

PV = nRT

for this scenario we want to rearrange to solve for Volume (V), meaning that the equation becomes

V = nRT / P

plugging in the values that we know from the information makes the equation

V = (32.5 mol x 0.0821 L*atm/mol*K * 279.55 K) / 4.39 atm

V = 169.91 L

meaning that the volume of the gas here is 169.91 L

Answer 2

Given the conditions, we can use the ideal gas law equation and solve for the volume variable. 

 

First we'll have to convert the temperature to K, to match the units in the gas constant, R:

6.40 +273 =279.4K

 

Then we substitute everything into the equation and rearrange:

PV=nRT

(4.39 atm)V = (32.5 moles)(0.08206 atm.L/mol.K)(279.4K)

V= [(32.5 moles)(0.08206 atm.L/mol.K)(279.4K)]/(4.39 atm)

   = 169 L