The shortest side of a right triangle measures 7 m.

Question

The shortest side of a right triangle measures 7 m. The lengths of the other two sides are consecutive integers - the hypotenuse being the longer of the two. Find the lengths of the other two sides

Answer 1

x=one leg

x+1=hypotenuse

7m=second leg

(x+1)^2=x^2+7^2

x^2+2x+1=x^2+49

subtract x^2 from both sides

2x+1=49

2x=48

x=24m

x+1=25m