One mol will always contain avogadro's number of atoms. Thus, this will basically be equal to whichever option has the most mol which you find by dividing each mass by the element's molar mass:
2g H / (1.008 g/mol H) = 1.98 mol H
7g Li / (6.941 g/mol Li) = 1.01 mol Li
8g He / (4.003 g/mol He) = 2.00 mol He
110g Ag / (107.868 g/mol Ag) = 1.02 mol Ag
200g Au / (196.967 g/mol Au) = 1.02 mol Au
Helium has the most number of mol out of all the options and will thus have the highest number of atoms.