J.R. S. answered 12/12/17
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Ph.D. in Biochemistry--University Professor--Chemistry Tutor
The actual van't Hoff factor will always be LOWER than the theoretical value. This has to do with using concentrations as opposed to activities in the theoretical values. The higher the concentration of solute, the lower will be the actual van't Hoff factor and the larger will be the discrepancy compared to theoretical values. This is because at high concentrations, there is a greater likelihood that two ions will collide and combine into a formula unit.
As for a comparison of KCl and KI, the I- ion is larger than the Cl- ion and so would be expected to be less strongly bonded to the K+ ion. From this, one would expect the van't Hoff factor for KI to be slightly greater than that for KCl, and following from this, it would expected to raise the b.p. more than KCl, assuming equal concentrations of the 2 salts.
J.R. S.
tutor
Not sure of a good explanation. Might be interesting to conpare KCl and KBr effect on other colligative properties such as vapor pressure lowering, freezing point depression or osmotic pressure. Also, the Br- ion reportedly has a radius of ~185 pm and Cl- is ~181 pm (not a large difference). For comparison, I- is ~ 216 pm. Also, I think that the ionic size isn't so straight forward, and can change depending on several variables. I'm not an expert in this, but I know ionic radius is not constant. Also,
Is is possible that there might be a slight impurity in KCl which would aid in increasing boiling point. Just a thought. Other than that, I'm not sure what's going on. Good luck to your student, and to you.
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12/12/17
Majid S.
12/12/17