Majid S.

asked • 12/12/17

The van't Hoff factor for KCl, KBr and KI.... different or same? Experimental and NOT Theoretical

The van't Hoff factor for KCl
The van't Hoff factor for KBr
The van't Hoff factor for KI

are NOT equal to each other!!!

My student is determining them experimentally expecting the same answers
Why they are not so?

The boiling point elevation of these solutions compared to water are expected to be equal?
If not, which one is expected to have the highest Boiling point? KCl or KI?

Best Regards
Majid

1 Expert Answer

By:

Majid S.

Thank you Dr for your appreciated reply
 
Experimentally my student found that KI has a higher boiling point than KCl which agrees with the analysis and the interpretation
But she found that KBr has a lower Boiling point than KCl even though the bromide ion is larger than the chloride ion!
 
What explanation can be given to such result? Is it normal?
The experiment is repeated 3 times till now and she is getting the same result.
Why do you think the KBr solution is found to have a lower boiling point than the KCl solution?
 
Best Regards
Majid Sarrouh
Chemistry teacher
Report

12/12/17

J.R. S.

tutor
Not sure of a good explanation. Might be interesting to conpare KCl and KBr effect on other colligative properties such as vapor pressure lowering, freezing point depression or osmotic pressure. Also, the Br- ion reportedly has a radius of ~185 pm and Cl- is ~181 pm (not a large difference).  For comparison, I- is ~ 216 pm.  Also, I think that the ionic size isn't so straight forward, and can change depending on several variables. I'm not an expert in this, but I know ionic radius is not constant. Also,
Is is possible that there might be a slight impurity in KCl which would aid in increasing boiling point. Just a thought. Other than that, I'm not sure what's going on. Good luck to your student, and to you.
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12/12/17

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