Nicole C.

asked • 12/10/17

If a solution of aspirin has a [OH-] = 4.4 x 10–12 M, what is the pH of the solution?

a)– 11.36
 
b)– 2.64
 
c)11.36
 
d)2.64
 
e)5.8

1 Expert Answer

By:

LaRita W. answered • 12/10/17

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Given the hydroxide concentration, we can calculate the pOH of the solution using the equation
pOH = -log[OH-]
        = -log (4.4 x 10-12)
        = 11.36
 
From there, we use the relationship between pH and pOH to convert to pH:
pH + pOH = 14
pH + 11.36 = 14
pH = 2.64

Choice D.

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LaRita W.

Alternatively, we could have started by converting the hydroxide concentration to hydronium ion concentration using the relationship
[OH-] x [H3O+] = 1.0 x 10-14
(4.4 x 10-12) x [H3O+] = 1.0 x 10-14
[H3O+] = (1.0 x 10-14)/(4.4 x 10-12)
            = 0.00227
 
From there, we can calculate pH using the equation
pH = -log[H3O+]
      = -log(0.00227)
      = 2.64
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12/10/17

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