Michael J. answered 12/09/17
Tutor
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Applying SImple Math to Everyday Life Activities
Let amount Meiling had at first = x
Let amount Fuminhad had at first = y
x + y = 280 eq1
Meiling has (1/2)x left. Fuminhad has (3/4)y left.
(1/2)x = (3/4)y
Multiply both sides of the equation by 4.
2x = 3y eq2
Next, substitute eq1 into eq2 to get eq2 in terms of one variable.
2(280 - y) = 3y
Solving for y,
560 - 2y = 3y
560 = 5y
112 = y
This is how much Fuminhad original had. Now take the difference between 280 and his amount to find Meiling's original amount.