Arturo O. answered 12/06/17
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T = half-life = 2 hrs
1/2 = (1)a2
a = √(1/2) ≅ 0.70711
Amount remaining as a function of time given an initial amount A0 and t in hours is
A(t) = A0(0.70711)t
This means that after each hour, you are left with 0.70711 times the amount at the start of the hour, which is 70.711%. Therefore, each hour it decays by (100 - 70.711)% = 29.289%.
Hourly decay rate is 29.289%