Al P. answered 12/20/17
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an+2 = -3an+1 - 2an ; a0=1, a1=-2
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a2 = -3(-2) - 2(1) = 4
a3 = -3(4) - 2(-2) = -8
a4 = -3(-8) - 2(4) = 16
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Conjecture: an = (-1)n2n , n≥0
a0= (-1)0 * 20 = 1
a1 = (-1)1 * 21 = -2
a2 = (-1)2 * 22 = 4 (the conjectured equation follows the same pattern we saw above)
Assume the conjecture is true for n=k: ak = -1k * 2k
Note that this is equivalent to the recursive formula ak+1= -2*ak
Now let n=k+1, if we can show it to be true for n=k+1, we're done.
ak+1= (-1)k+1 * 2k+1 = (-1)(2)(-1k * 2k ) = -2(ak )
Done.