Kahroline D. answered 08/06/14
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Since the walkway is 2ft on all sides, we have 4ft of walkway for each of length L, and width W
We know that total length L = 3(total width W), or L = 3W.
Hence the length of the pool l = L - 4, and the width of the pool w = W - 4
a) area of the pool is length times width, but each of these has the 4 ft of walkway to consider (as described above):
A = lw
A = (L - 4)(W - 4)
A = [(3W) - 4](W - 4)
A = (3W - 4)(W - 4)
A = 3W(W - 4) - 4(W - 4)
A = 3W2 - 16W + 16
b) if the total width W = 10, then the area of the pool is:
A = 3(10)2 - 16(10) + 16
A = 3(100) - 160 + 16
A = 316 - 160
A = 156 ft2
c) if the total width W = 9, then the area of the pool is:
A = 3(9)2 - 16(9) + 16
A = 3(81) - 144 + 16
A = 243 - 144 + 16
A = 115 ft2
Kahroline D.
Francisco,
If the walkway goes all around the pool and is two feet wide - then it not only borders the length of the pool, but also its width. Thank you for your comment though - I suggest drawing a schematic to understand (pictures always help)
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08/06/14
Francisco E.
08/06/14