
Kenneth S. answered 11/30/17
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Expert Help in Algebra/Trig/(Pre)calculus to Guarantee Success in 2018
These problems are easy if you let p = plane's speed (constant) in still air and let w = wind speed.
We then present the facts in a D R T chart, where distance D = rate (R) multiplied by time T:
with tailwind: 2000 p+w T
into tailwind: 1800 p-w T.
T = 2000/(p+w)
T = 1800/(p-w)
These two T values are the same, and p = 760 km.
Therefore 2000/(760+w) = 1800/(760-w). Solve this equation; begin by cross-multiplying.
I leave you to do (1) Study this approach, and if you agree, (2) solve for w.
(I believe the student can do some heavy lifting, after receiving good guidance.)